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The equation holds in imperial units as well. The length of the 2 second pendulum needs to be in feet AND the value of g in ft/sec2.


π^2 ≈ 32 to you?


Solving the equation for pi we get:

PI = sqrt(g/L)

g = 9.81. L=1

or

g = 32.174. L=3.174

Either way works to approximately pi. There is a particular length where it works out exactly to pi which is about 3.2 feet, or about 1 meter. My point was that equations like that remain true regardless of units.

The reason pi squared is approximately g is that the L required for a pendulum of 2 seconds period is approximately 1 meter.


Replace s in your calculation with imperial s instead of metric s and it isn't imperial feet per metric seconds.


Imperial seconds were very, very close to metric seconds.




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