Did you read the remark at the end of my comment? In the practical cases I was e... | Hacker News

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		sbazerque on Sept 4, 2024 \| parent \| context \| favorite \| on: Keeping CALM: When distributed consistency is easy... Did you read the remark at the end of my comment? In the practical cases I was exploring, that combinatorial explosion does not happen. It's relaxed in the sense that it is coordination-free.

j-pb on Sept 5, 2024 [–]

Not sure what you mean.

I'm talking about the "relaxed" P' being defined via the power set of S.

2^S= {s | s ⊆ S}

Now if all your P is only a mapping then

P'(S) = {<s, P(s)> | s ∈ S}

but then your "coordination free" P was monotonic anyways.

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